Question

Simplify $\sin \left(ax+b\right)\cos \left(ax+b\right)$

Answer 1

Given that,

$\sin (ax+b)\cos (ax+b)$

$=\frac{2}{2}\sin (ax+b)\cos (ax+b)$

$=\frac{1}{2}\left[2\sin (ax+b)\cos (ax+b)\right]$

$=\frac{1}{2}\sin 2(ax+b)\therefore \sin 2\theta =2\sin \theta \cos \theta$

Hence, this is the answer.