Question

Simplify $\sqrt[4]{4\sqrt[3]{3x^2}}$ and express the result in the exponential form of x.

Answer 1

$\sqrt[4]{4\sqrt[3]{3x^2}}=(x^2{)}^{\frac{1}{3}}{)}^{\frac{1}{4}}=(x^2{)}^{\frac{1}{3}\times \frac{1}{4}}=(x^2{)}^{\frac{1}{12}}=x^{2\times \frac{1}{12}}=x^{\frac{1}{6}}$