Given, #160; √(72)+√(800) √(18) = √(2× 6^2)+√(2× 20^2) √(2× 3^2) = 6√(2)+20√(2) 3√(2) = 23√(2) #160; ...

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Byju's Answer

Standard VIII

Mathematics

Finding Square Root of a Number

Simplify: √72...

Question

$S i m p l i f y : \sqrt{72} + \sqrt{800} - \sqrt{18}$

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Solution

given, $\sqrt{72} + \sqrt{800} - \sqrt{18}$

$= \sqrt{2 \times 6^{2}} + \sqrt{2 \times 20^{2}} - \sqrt{2 \times 3^{2}}$

$= 6 \sqrt{2} + 20 \sqrt{2} - 3 \sqrt{2}$

$= 23 \sqrt{2}$

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Similar questions

Simplify√72-√800-√18

Q. The simplified value of

\sqrt{72} + \sqrt{800} - \sqrt{18}

Simplify

(i) $3 \sqrt{45} - \sqrt{125} + \sqrt{200} - \sqrt{50}$
(ii) $2 \frac{\sqrt{30}}{\sqrt{6}} - 3 \frac{\sqrt{140}}{\sqrt{28}} + \frac{\sqrt{55}}{\sqrt{99}}$
(iii) $\sqrt{72} + \sqrt{800} - \sqrt{18}$

Simplify:

3√45 - √125 + √200 - √50

2√30/√6 - 3√140/√28 + √55/√99

√72 + √800 - √18

Root (72) + root (800) - root (18)

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Simplify:√72+√800−√18

given, √72+√800−√18=√2×62+√2×202−√2×32=6√2+20√2−3√2=23√2

$S i m p l i f y : \sqrt{72} + \sqrt{800} - \sqrt{18}$

given, $\sqrt{72} + \sqrt{800} - \sqrt{18}$

$= \sqrt{2 \times 6^{2}} + \sqrt{2 \times 20^{2}} - \sqrt{2 \times 3^{2}}$

$= 6 \sqrt{2} + 20 \sqrt{2} - 3 \sqrt{2}$

$= 23 \sqrt{2}$