Question

Simplify: $\text{15-}\left[\left(3\right)\left\{4-\left(7-3\right)\right\}÷3\left\{5+\left(3\right)\times \left(6\right)\right\}\right]$

Answer 1

We have to use BODMAS Rule in this question.

BODMAS stands for Brackets, Of, Division, Multiplication, Addition, Subtraction

First we open brackets, in brackets order will be , BAR,PARENTHESES, CURLY BRACKETS, SQUARE BRACKETS

$$\begin{gathered} \text{15-}\left[\left(3\right)\left\{4-\left(7-3\right)\right\}÷3\left\{5+\left(3\right)\times \left(6\right)\right\}\right] \\ =15-\left[3\left\{4-\left(7-3\right)\right\}÷3\left\{5+3\times 6\right\}\right]\left[\mathrm{Opening}\mathrm{Parentheses}\right] \\ =15-\left[3\left\{4-4\right\}÷3\times 23\right]\left[\mathrm{Opening}\mathrm{Curly}\mathrm{Brackets}\right] \\ =15-\left[0÷69\right] \\ =15-0\left[\mathrm{Opening}\mathrm{Square}\mathrm{bracket}\right] \\ =15 \end{gathered}$$

Hence, answer is $15$