Simplify the expression $(2 b^{3} c^{2} + b^{2} c - 4 b c) - (b^{3} c^{2} - b^{2} c - 4 b c)$ .

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b^{3} c^{2}

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b^{3} c^{2} + 2 b^{2} c

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b^{3} c^{2} + 2 b^{2} c - 8 b c

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Solution

The correct option is D $b^{3} c^{2} + 2 b^{2} c$
On simplification, we get
$(2 b^{3} c^{2} + b^{2} c - 4 b c) - (b^{3} c^{2} - b^{2} c - 4 b c)$
$\Rightarrow 2 b^{3} c^{2} + b^{2} c - 4 b c - b^{3} c^{2} + b^{2} c + 4 b c$
$\Rightarrow b^{3} c^{2} + 2 b^{2} c$

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