Simplify the expression: $4 x^{3} [(3 x - x^{2}) - 1] + (x^{2}) [x + 1]$ .

- 4 x^{5} - 12 x^{4} - 3 x^{3} + x^{2}

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- 4 x^{5} + 12 x^{4} + 3 x^{3} + x^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 4 x^{5} + 12 x^{4} - 3 x^{3} - x^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 4 x^{5} + 12 x^{4} - 3 x^{3} + x^{2}

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Solution

The correct option is C $- 4 x^{5} + 12 x^{4} - 3 x^{3} + x^{2}$
$4 x^{3} [(3 x - x^{2}) - 1] + (x^{2}) [x + 1]$
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
$=$ $4 x^{3} [(3 x - x^{2}) - 1] + (x^{2}) [x + 1]$
$=$ $4 x^{3} [3 x - x^{2} - 1] + x^{3} + x^{2}$
$=$ $12 x^{4} - 4 x^{5} - 4 x^{3} + x^{3} + x^{2}$
$=$ $- 4 x^{5} + 12 x^{4} - 3 x^{3} + x^{2}$

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