Question

Simplify the expression $2(a^2+ab)+3-ab$ and find its value when$a=5$and $b=-3.$

Answer 1

Simplifying the given expression:

From the given details we get to know that $a=5$and $b=-3.$

We have,

$2(a^2+ab)+3-ab$$=$ $2a^2+2ab+3-ab$

$=$$2a^2+ab+3$

On substituting the value of $x$ in the above algebraic equation and simplifying we get

$2a^2+ab+3$ $=$$(2\times 5^2)+(5\times (-3\left)\right)+3$

$=(2\times 25)+(-15)+3$

$=50–15+3$

$=53–15$

$=38$

Therefore, if $a=5$ and $b=-3.$ then $2a^2+ab+3$ $=38$.