Question

Simplify the expression $\frac{6p^2-150}{p^2-3x-40}$

• A. $\frac{6(p-5)}{p-8}$
• B. $\frac{6(p-5)}{p+8}$
• C. $\frac{6(p+5)}{p-8}$
• D. none of the above

Answer 1

The correct option is A $\frac{6(p-5)}{p-8}$

$\frac{6p^2-150}{p^2-3x-40}=\frac{6(p^2-25)}{p^2-8x+5x-40}=\frac{6(p-5)(p+5)}{p(p-8)+5(p-8)}=\frac{6(p-5)(p+5)}{(p-8)(p+5)}=\frac{6(p-5)}{p-8}$