Simplify the expression: 1sinθ+cosθ+1sinθ−cosθ
Given: 1sinθ+cosθ+1sinθ−cosθ
By taking LCM,
=sinθ−cosθ+sinθ+cosθ(sinθ+cosθ)(sinθ−cosθ)
=2sinθ(sin2θ−cos2θ) Using the identity, sin2θ=1−cos2θ
=2sinθ[(1−cos2θ)−cos2θ] =2sinθ(1−2cos2θ)
The expression E=1+cosθ+sinθ1+cosθ−sinθ can be simplified to