Simplify the following -1 -30 - 20- - 5 02 7-9- 7-6 - 715

(1) nbsp;[(3)^0 + (2)^0] × (5) ^0 = (1+1) × 1 = 2 nbsp;× 1 = 2 (2) (7^ 9× 7^ 6) × 7^15 = 7^ 9 6× 7^15 =7^ 15+15 [∵ a^m × a^n=a^m+n] =7^0=1 nbsp; ...

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Byju's Answer

Standard IX

Mathematics

Product Law

Simplify the ...

Question

Simplify the following :
(1) $[(3)^{0} + (2)^{0}] \times (5)^{0}$
(2) $(7^{- 9} \times 7^{- 6}) \times 7^{15}$

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Solution

(1) $[(3)^{0} + (2)^{0}] \times (5)^{0}$
= (1+1) $\times$ 1
= 2 $\times$ 1
= 2
(2) $(7^{- 9} \times 7^{- 6}) \times 7^{15}$
$= 7^{- 9 - 6} \times 7^{15} = 7^{- 15 + 15} [∵ a^{m} \times a^{n} = a^{m + n}] = 7^{0} = 1$

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Simplify the following : (1) [(3)0+(2)0]×(5)0 (2) (7−9×7−6)×715

(1) [(3)0+(2)0]×(5)0 = (1+1) × 1 = 2 × 1 = 2 (2) (7−9×7−6)×715 =7−9−6×715=7−15+15 [∵ am×an=am+n]=70=1

Simplify the following :
(1) $[(3)^{0} + (2)^{0}] \times (5)^{0}$
(2) $(7^{- 9} \times 7^{- 6}) \times 7^{15}$

(1) $[(3)^{0} + (2)^{0}] \times (5)^{0}$
= (1+1) $\times$ 1
= 2 $\times$ 1
= 2
(2) $(7^{- 9} \times 7^{- 6}) \times 7^{15}$
$= 7^{- 9 - 6} \times 7^{15} = 7^{- 15 + 15} [∵ a^{m} \times a^{n} = a^{m + n}] = 7^{0} = 1$