Question

Simplify the following:

$3-1\frac{1}{6}-\frac{7}{15}$

Answer 1

we can write $3$ as $\frac{3}{1}$

Step1:- First convert the mixed fraction into an improper fraction:

$1\frac{1}{6}=\frac{7}{6}$

Step 2:- Make the denominator of both fractions same.

Multiply $\frac{3}{1}$by $30$

$\frac{3}{1}=\frac{3\times 30}{1\times 30}=\frac{90}{30}$

Multiply $\frac{7}{6}$ by $5$.

$\frac{7}{6}$$=\frac{7\times 5}{6\times 5}=\frac{35}{30}$

Multiply $\frac{7}{15}$by $2$.

$\frac{7}{15}=\frac{7\times 2}{15\times 2}=\frac{14}{30}$

Step 3:- Add $\frac{35}{30}$ and $\frac{14}{30}$

$\frac{35}{30}$$+$$\frac{14}{30}$$=\frac{35+14}{30}=\frac{49}{30}$

Step 4:- Subtract $\frac{49}{30}$ from $\frac{90}{30}$

$\frac{90}{30}$$-$$\frac{49}{30}$$=\frac{90-49}{30}=\frac{41}{30}$

Step 4:- Convert the improper fraction into a mixed fraction.

$\frac{41}{30}=1\frac{11}{30}$

Hence, $1\frac{11}{30}$ is the required solution.