Question

Simplify the following:

$3\frac{2}{9}+2\frac{1}{3}+2\frac{7}{12}$

Answer 1

Step1:- First convert the mixed fraction into an improper fraction:

$3\frac{2}{9}=\frac{29}{9}$

$2\frac{1}{3}=\frac{7}{3}$

$2\frac{7}{12}$$=\frac{31}{12}$

Step 2:- Make the denominator of both fractions same.

Multiply $\frac{29}{9}$by $4$

$\frac{29}{9}=\frac{29\times 4}{9\times 4}=\frac{116}{36}$

Multiply $\frac{7}{3}$ by $12$.

$\frac{7}{3}$$=\frac{7\times 12}{3\times 12}=\frac{84}{36}$

Multiply $\frac{31}{12}$by $3$.

$\frac{31}{12}=\frac{31\times 3}{12\times 3}=\frac{93}{36}$

Step 3:- Add all the fraction

$\frac{116}{36}+\frac{84}{36}+\frac{93}{36}=\frac{116+84+93}{36}=\frac{293}{36}$

Step 4:- Convert the improper fraction into a mixed fraction.

$\frac{293}{36}=8\frac{5}{36}$

Hence, $8\frac{5}{36}$ is the required solution.