Question

Simplify the following:
$4\frac{2}{3}-9\frac{3}{5}÷2\frac{2}{15}=$ $\frac{x}{6}$. Find x.

Answer 1

We have.

$4\frac{2}{3}-9\frac{3}{5}÷2\frac{2}{15}=\frac{x}{6}$

$\Rightarrow \frac{14}{3}-\frac{48}{5}÷\frac{32}{15}=\frac{x}{6}$

$\Rightarrow \frac{14}{3}-\frac{48}{5}\times \frac{15}{32}=\frac{x}{6}$ [Divide $15$ by $5=3$ and $48$ & $32$ by $16$ we get $3,2$]

$\Rightarrow \frac{14}{3}-\frac{3}{1}\times \frac{3}{2}=\frac{x}{6}$

$\Rightarrow \frac{14}{3}-\frac{9}{2}=\frac{x}{6}$

$\Rightarrow \frac{28-27}{6}=\frac{x}{6}$ [cancle $6$ both sides]

$\Rightarrow 28-27=x$

$\therefore x=1$

Hence,

The value of $x=1$ .