Question

Simplify the following

$(4x^{2}y{z}^3-16x^3{y}^2{z}^2+12x^5{y}^7{z}^2)÷\left(2x^{2}y{z}^2\right)$

Answer 1

Simplify the given expression

$$\begin{gathered} (4x^{2}y{z}^3-16x^3{y}^2{z}^2+12x^5{y}^7{z}^2)÷\left(2x^{2}y{z}^2\right)=\frac{4x^{2}y{z}^3-16x^3{y}^2{z}^2+12x^5{y}^7{z}^2}{2x^{2}y{z}^2} \\ =\frac{4x^{2}y{z}^3}{2x^{2}y{z}^2}+\frac{-16x^3{y}^2{z}^2}{2x^{2}y{z}^2}+\frac{12x^5{y}^7{z}^2}{2x^{2}y{z}^2} \\ =2z-8xy+6x^3{y}^6 \\ So,(4x^{2}y{z}^3-16x^3{y}^2{z}^2+12x^5{y}^7{z}^2)÷\left(2x^{2}y{z}^2\right)=2z-8xy+6x^3{y}^6 \end{gathered}$$