Simplify the following algebraic expression.
$6 m + 3 n^{2} - 8 n^{2} + 2 n$

- 5 n^{2} - 2 n + 6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 5 n^{2} + 2 n + 6 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5 n^{2} - 2 n + 6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 n^{2} + 2 n - 6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $- 5 n^{2} + 2 n + 6 m$
A polynomial is in standard form when its term of highest degree is first, its term of 2nd highest is 2nd and so on.

We group together the like terms and simplify the given algebraic expression $6 m + 3 n^{2} - 8 n^{2} + 2 n$ to write it in standard form of polynomial as follows:

$6 m + 3 n^{2} - 8 n^{2} + 2 n = (3 n^{2} - 8 n^{2}) + 2 n + 6 m = - 5 n^{2} + 2 n + 6 m$

Hence, $6 m + 3 n^{2} - 8 n^{2} + 2 n = - 5 n^{2} + 2 n + 6 m$ .

Suggest Corrections

Similar questions

The arithmetic mean (A.M.) of the observations $1.3.5, 3.5.7, 5.7.9 . . . (2 n - 1) . (2 n + 1) . (2 n + 3)$ is

Q. Simplify :

(6 m - n) (36 m^{2} + 6 m n + n^{2}) - (3 m + 2 n)^{3}

Is the sequence, whose general term is 5n² + 2n + 3 an AP?

The sum of the following series, $\frac{1}{3}^{n} c_{1} + \frac{(1^{2} + 2^{2})}{5}^{n} c_{2} + \frac{(1^{2} + 2^{2} + 3^{2})}{7}^{n} c_{3}$ + ...... upto n terms is

Q. The Arithmetic Mean of the observations

1.3.5, 3.5.7, 5.7.9, . . ., (2 n - 1) (2 n + 1) (2 n + 3)

(\forall n \in N)

Join BYJU'S Learning Program

Simplify the following algebraic expression.6m+3n2−8n2+2n

Simplify the following algebraic expression.
$6 m + 3 n^{2} - 8 n^{2} + 2 n$