Question

Simplify the following algebraic expression by removing grouping symbols.
$2a–[4b–\{4a–3(2a–b)\left\}\right]$

Answer 1

Given $2a–[4b–\{4a–3(2a–b)\left\}\right]$
First we have to remove the parentheses, then remove braces, and then the square brackets.
Then we get,
$2a–[4b–\{4a–3(2a–b)\left\}\right]$
$=2a–[4b–\{4a–6a+3b\left\}\right]$
$=2a–[4b–\{–2a+3b\left\}\right]$
$=2a–[4b+2a–3b]$
$=2a–[b+2a]$
$=2a–b–2a$
$=–b$