Question

Simplify the following expression.

$(2e^{2/3}{)}^3\times (9e^2{)}^{3/2}÷e^{-3}$

Answer 1

$\frac{2^3\times (e^{\frac{2}{3}}{)}^3\times 9^{\frac{3}{2}}\times (e^2{)}^{\frac{3}{2}}}{\frac{1}{e^3}}$

$=8\times e^2\times (3^2{)}^{\frac{3}{2}}\times (e^2{)}^{\frac{3}{2}}\times e^3$

$=8\times e^5\times 3^3\times e^3$

$=216e^8$