Given expression: (5x−7y)3+(5x+7y)3
It is in the form of a3+b3
We know that, a3+b3=(a+b)(a2−ab+b2)
(5x−7y)3+(5x+7y)3 =[(5x−7y)+(5x+7y)] ×=[(5x−7y)2−(5x−7y)×(5x+7y) +(5x+7y)2]
=(10x) ×[(5x−7y)2−(5x−7y)(5x+7y) +(5x+7y)2]
-------- eq. (1)
(1 Mark)
Now,
(5x−7y)2
It is in the form of (a−b)2
We know that,
(a−b)2=a2+b2−2ab⇒(5x−7y)2=(5x)2+(7y)2−2×5x×7y=25x2+49y2−70xy
Now,
(5x−7y)(5x+7y)
It is in the form of (a−b)(a+b)
We know that,
(a−b)(a+b)=a2−b2⇒(5x)2−(7y)2 = 25x2−49y2
Now,
(5x+7y)2
It is in the form of (a+b)2
We know that,
(a+b)2=a2+b2+2ab⇒(5x+7y)2=(5x)2+(7y)2+2×5x×7y=25x2+49y2+70xy
(2 Marks)
By substituting, (5x−7y)2; (5x−7y)(5x+7y) and (5x+7y)2 in eq. (1); we get,
=(10x) ×[(25x2+49y2−70xy) −(25x2−49y2) +(25x2+49y2+70xy)]
=(10x)[25x2+147y2]=250x3+1470xy2
(1 Mark)