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Question

Simplify the following expression:

1a+1b+c1a1b+c(1+b2+c2a22bc):abcabc

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Solution

1a+1b+c1a1b+c=a+b+cb+ca

1+b2+c2a22bc=b2+c2+2bca22bc=(a+b+c)(b+ca)2bc

1a+1b+c1a1b+c(1+b2+c2a22bc):abcabc=a+b+cb+ca×(a+b+c)(b+ca)2bc×abcabc=a(a+b+c)22(abc)

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