Simplify the following expression such that the result has positive exponents: $(25 M^{2} N^{- 4})^{1 / 2} (M^{3} N^{1 / 2})^{2}$ .

5 M^{7} / N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 M^{5} / N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 M^{5} / N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 M^{6} / N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $5 M^{7} / N$
$(25 M^{2} N^{- 4})^{1 / 2} (M^{3} N^{1 / 2})^{2}$
$= (5 M N^{- 2}) (M^{6} N)$
$= 5 M^{7} N^{- 1} = 5 M^{7} / N$

Suggest Corrections

Similar questions

(25 M^{2} N^{- 4})^{1 / 2} (M^{3} N^{1 / 2})^{2}

{(\frac{1}{2^{3}})}^{2}

(- 4)^{5} \div (- 4)^{8}

Question 2(i)
Simplify and express the result in power notation with positive exponent:

$(- 4)^{5} \div (- 4)^{8}$

Question 2(ii)
Simplify and express the result in power notation with positive exponent:

${(\frac{1}{2^{3}})}^{2}$

Join BYJU'S Learning Program