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Question

Simplify the following expression;
x(2x+3y−z)+y2(3x+z−2y)−z(2x+3z−y).

A
2y3+3xy2+2zy2+2x24z2+3xy+zy+3zx
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B
2y3+3xy2+zy2+2x23z2+3xy+zy3zx
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C
2y33xy2+2zy2+2x23z2+3xy+zy3zx
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D
2y3+3xy2+zy2+2x2+z2+3xy+zy3zx
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Solution

The correct option is B 2y3+3xy2+zy2+2x23z2+3xy+zy3zx
Given expression is,
x(2x+3yz)+y2(3x+z2y)z(2x+3zy)
=2x2+3xyxz+3xy2+zy22y32zx3z2+zy
Grouping all the like terms together we get,
=2x2+3xy(zx+2zx)+3xy2+zy22y33z2+zy
=2y3+3xy2+zy2+2x23z2+3xy+zy3zx

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