The correct option is B −2y3+3xy2+zy2+2x2−3z2+3xy+zy−3zx
Given expression is,
x(2x+3y−z)+y2(3x+z−2y)−z(2x+3z−y)
=2x2+3xy−xz+3xy2+zy2−2y3−2zx−3z2+zy
Grouping all the like terms together we get,
=2x2+3xy−(zx+2zx)+3xy2+zy2−2y3−3z2+zy
=−2y3+3xy2+zy2+2x2−3z2+3xy+zy−3zx