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Question

Simplify the following expressions :

(i) (11+11)(1111)

(ii) (5+7)(57)

(iii) (82)(8+2)

(iv) (3+3)(33)

(v) (52)(5+2)

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Solution

(i) (11+11)(1111)=(11)2(11)2 { (a+b)(ab)=a2b2}=12111=110

(ii) (5+7)(57)=(5)2(7)2 { (a+b)(ab)=a2b2}=257=18

(iii) (82)(8+2)=(8)2(2)2 { (a+b)(ab)=a2b2}=82=6

(iv) (3+3)(33)=(3)2(3)2 { (a+b)(ab)=a2b2}=93=6

(v) (52)(5+2)=(5)2(2)2 { (a+b)(ab)=a2b2}=52=3


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