Simplify the following- 1 2 4 - 1 2 5 - 1 2 6

The correct option is A ( 1 2 #160;) #160;^ 15 we know, a^m*a^n=(a)^m+n so, ( 1 2 #160; ) #160; ^ 4 ×( 1 2 #160; ) #160; ^ 5 ...

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Byju's Answer

Standard VII

Mathematics

Exponents with Like Bases

Simplify the ...

Question

Simplify the following:
${(\frac{1}{2})}^{4} \times {(\frac{1}{2})}^{5} \times {(\frac{1}{2})}^{6}$

{(\frac{1}{2})}^{15}

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{(\frac{1}{2})}^{5}

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{(\frac{1}{2})}^{10}

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None of these

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Solution

The correct option is A ${(\frac{1}{2})}^{15}$
we know,
$a^{m} * a^{n} = (a)^{m + n}$
so,
${(\frac{1}{2})}^{4} \times {(\frac{1}{2})}^{5}$
$= {(\frac{1}{2})}^{6}$
so,

${(\frac{1}{2})}^{4 + 5 + 6}$
$= {(\frac{1}{2})}^{15}$

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Q. evaluate

\frac{{(\frac{1}{2})}^{5} - {(\frac{1}{2})}^{6}}{{(\frac{1}{2})}^{3} - {(\frac{1}{2})}^{5}}

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Simplify the following:(12)4×(12)5×(12)6

The correct option is A (12)15we know,am∗an=(a)m+nso,(12)4×(12)5=(12)6so,(12)4+5+6=(12)15

Simplify the following:
${(\frac{1}{2})}^{4} \times {(\frac{1}{2})}^{5} \times {(\frac{1}{2})}^{6}$

The correct option is A ${(\frac{1}{2})}^{15}$
we know,
$a^{m} * a^{n} = (a)^{m + n}$
so,
${(\frac{1}{2})}^{4} \times {(\frac{1}{2})}^{5}$
$= {(\frac{1}{2})}^{6}$
so,

${(\frac{1}{2})}^{4 + 5 + 6}$
$= {(\frac{1}{2})}^{15}$