Question

Simplify the following:
${\left(\frac{3^5}{3^3}\right)}^5\times 3^{-6}$

Answer 1

${\left(\frac{3^5}{3^3}\right)}^5\times 3^{-6}$
${\left(3^{5-3}\right)}^5\times 3^{-6}$ $(\because \frac{a^m}{a^n}=a^{m-n})$
$={\left(3^2\right)}^5\times 3^{-6}$ $(\because {\left(a^m\right)}^n=a^{mn})$
$=3^{10}\times 3^{-6}=3^4=81$