Question

Simplify the following using law of exponents.
$(-3{)}^3\times (-3{)}^{10}\times (-3{)}^7$

• A. $3^{20}$
• B. $3^{40}$
• C. $3^{60}$
• D. $3^{10}$

Answer 1

The correct option is A $3^{20}$

we know,

$a^m\ast a^n\ast a^p=a^{m+n+p}$

so,

$(-3{)}^3\ast (-3{)}^{10}\ast (-3{)}^7=(-3{)}^{3+10+7}$

$=(-3{)}^{20}$

$=(3{)}^{20}$