Question

Simplify the following using law of exponents.
$(-7{)}^7\times (-7{)}^8$=$(-7{)}^m$ .Find m

Answer 1

we know,

$a^m\ast a^n=(a{)}^{m+n}$

so,

$(-7{)}^7\ast (-7{)}^8=(-7{)}^{7+8}$

$=(-7{)}^{15}$

$⟹m=15$