Question

Simplify the following using laws of exponent
$[7^8\times {12}^8]÷[{14}^8\times 6^8]$

Answer 1

We have,

$[7^8\times {12}^8]÷[{14}^8\times 6^8]$

$=\frac{7^8\times {12}^8}{{14}^8\times 6^8}$

$=\frac{7^8\times (2\times 6{)}^8}{(2\times 7{)}^8\times 6^8}$

$=\frac{7^8\times 2^8\times 6^8}{2^8\times 7^8\times 6^8}$

$=1$

Hence, this is the answer.