Question

Simplify the given equation (x3−7x2+20x−12)÷(x−4)(x3−7x2+20x−12)÷(x−4).

Answer 1

$(x-4)(x^2-3x+8)=0$

For, $x^2-3x+8$

$⟹x=\frac{3\pm \sqrt{9-4\left(8\right)}}{2}$

$⟹x=\frac{3\pm i23}{2}$

and For, $x-4=0$

$⟹x=4$