Simplify the given logarithmic function:
$(x^{2} + 1) log x$

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Solution

$(x^{2} + 1) log x = x^{2} log x + log x$
$= log x^{x^{2}} + log x$
$= log (x^{x^{2}} . x)$
$= log (x^{(x^{2} + 1)})$

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