Simplify the polynomial and write it in standard form:
$- 3 (x^{3} - x^{2} - 2 x - 5) - (4 x^{3} - 7 x - 1)$

- 7 x^{3} + 3 x^{2} + 13 x + 16

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7 x^{3} + 2 x^{2} + 11 x + 16

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- 6 x^{3} + 3 x^{2} + 12 x + 14

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- 4 x^{3} + 3 x^{2} + 11 x + 15

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Solution

The correct option is B $- 7 x^{3} + 3 x^{2} + 13 x + 16$
Solve the polynomial as follows:
$- 3 (x^{3} - x^{2} - 2 x - 5) - (4 x^{3} - 7 x - 1)$
$= - 3 x^{3} + 3 x^{2} + 6 x + 15 - 4 x^{3} + 7 x + 1$
$= - 7 x^{3} + 3 x^{2} + 13 x + 16$

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Similar questions

(3 x - 2 x) \times (4 x^{3} - 3 x^{2})

- 4 x^{3} + 3 x^{2} + 11 x - 9

x = - 2

x^{3}

5 + 2 x + 3 x^{2} - 7 x^{3}

What must be subtracted from $4 x^{3} - 3 x + 5$ to get $2 x^{2} - 3 x^{3} + 5 x - 2$ ?

4 x^{3} - 3 x + 5

2 x^{2} - 3 x^{3} + 5 x - 2

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