Simplify the square root of the polynomial using factorisation method: $\frac{a^{2}}{a^{2} - b^{2}} + \frac{b^{2}}{b^{2} - a^{2}}$

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1$
$\sqrt{\frac{a^{2}}{a^{2} - b^{2}} + \frac{b^{2}}{b^{2} - a^{2}}}$
$=$ $\sqrt{\frac{a^{2}}{a^{2} - b^{2}} - \frac{b^{2}}{a^{2} - b^{2}}}$
$\sqrt{\frac{a^{2} - b^{2}}{a^{2} - b^{2}}}$
$=$ $\sqrt{1}$
$= 1$

Suggest Corrections

Similar questions

x = \frac{\sqrt{a^{2} + b^{2}} + \sqrt{a^{2} - b^{2}}}{\sqrt{a^{2} + b^{2}} - \sqrt{a^{2} - b^{2}}}

b^{2} = \frac{2 a^{2} x}{x^{2} + 1}

a^{2} b^{2} x^{2} - (a^{2} + b^{2}) x + 1 = 0

x = \frac{\sqrt{a^{2} + b^{2}} + \sqrt{a^{2} - b^{2}}}{\sqrt{a^{2} + b^{2}} - \sqrt{a^{2} - b^{2}}}

a^{2} - b^{2} = \frac{2 a^{2}}{x^{2} + 1}

x = \frac{\sqrt{a^{2} + b^{2}} + \sqrt{a^{2} - b^{2}}}{\sqrt{a^{2} + b^{2}} - \sqrt{a^{2} - b^{2}}}

b^{2} = \frac{2 a^{2} x}{x^{2} + 1}

x = \frac{\sqrt{a^{2} + b^{2}} + \sqrt{a^{2} - b^{2}}}{\sqrt{a^{2} + b^{2}} - \sqrt{a^{2} - b^{2}}}

b^{2} = \frac{{2 a x}^{2} x}{x^{3} + 1}

Join BYJU'S Learning Program