Question

Simplify using BODMAS rule: $\left[\right((100+x)x^4)÷x^2]\times 2-(x+x^2-1)$.

• A. $x^3+199x^2-x+1$
• B. $2x^3+199x^2-x+1$
• C. $2x^3-199x^2-x+1$
• D. $2x^3+199x^2-x-1$

Answer 1

The correct option is B $2x^3+199x^2-x+1$

$\left[\right((100+x)x^4)÷x^2]\times 2-(x+x^2-1)$
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
$=$ $\left[\right((100+x)x^4)÷x^2]\times 2-(x+x^2-1)$
$=$ $\frac{(100+x)\left(x^4\right)}{x^2}\times 2-x-x^2+1$
$=$ $200x^2+2x^3-x-x^2+1$
$=$ $2x^3+199x^2-x+1$