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Question

Simplify using suitable identities:
(2x+5y3z)2

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Solution

We have (a+b+c)2=a2+b2+c2+2ab+2bc+2ca
where a=2x,b=5y,c=3z
(2x+5y3z)2=(2x)2+(5y)2+(3z)2+2×2x×5y+2×5y×3z+2×3z×2x
=4x2+25y2+9z220xy30yz+12xz

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