Question

Simplify using the rules of exponents;
$\frac{{12}^4\times 9^3\times 4}{27\times 8^2}$

Answer 1

Now,

$\frac{{12}^4\times 9^3\times 4}{27\times 8^2}$

$=\frac{(3\times 4{)}^4\times 3^6\times 4}{3^3\times 2^6}$

$=\frac{4^5\times 3^{10}}{3^3\times 2^6}$

$=\frac{2^{10}\times 3^{10}}{3^3\times 2^6}$

$=2^4\times 3^7$.