Simplify:

$(v)$ $6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2}$

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Solution

$Step:$ Simplify the expression

By grouping the terms having the same literals and adding we get,

$6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2}$

$= (6 a^{2} + 2 a^{2} - 4 a^{2}) + (- 3 b^{2} + 5 b^{2})$

$= a^{2} (6 + 2 - 4) + b^{2} (- 3 + 5)$

$= a^{2} (4) + b^{2} (2)$

$= 4 a^{2} + 2 b^{2}$

$∴ 6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2} = 4 a^{2} + 2 b^{2}$

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6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2}

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