Simplify.Write the expression using only positive exponents.
$x^{- 2} \cdot x^{0}$

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Solution

Simplifying the expression
$x^{- 2} \cdot x^{0}$
$= x^{- 2} \cdot 1$ (Using exponent law $a^{0} = 1$ )
$= \frac{1}{x^{2}} \cdot 1$ (Using exponent law $a^{- n} = \frac{1}{a^{n}}$ )
$= \frac{1}{x^{2}}$
Hence, the expression is $x^{- 2} \cdot x^{0} = \frac{1}{x^{2}}$

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