Simplify.Write the expression using only positive exponents.
$y^{- 8} \cdot y^{3}$

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Solution

Simplifying the expression
$y^{- 8} \cdot y^{3}$
$= y^{- 8} \cdot y^{3}$
$= y^{- 8 + 3}$ (Using exponent law $\frac{a^{m}}{a^{n}} = a^{m - n}$ )
$= y^{- 5}$
$= \frac{1}{y^{5}}$ (Using exponent law $a^{- n} = \frac{1}{a^{n}}$ )
Hence, the expression is $y^{- 8} \cdot y^{3} = \frac{1}{y^{5}}$

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