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B
2x3−3x2+3x+3
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C
2x3+3x2+2x+3
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D
2x3−3x2−2x+3
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Solution
The correct option is D2x3−3x2−2x+3 (x + 1)(x - 1)(2x - 3) Using the identity (a+b)(a−b)=a2−b2 for (x+1)(x−1) =(x2−12)×(2x−3) =x2(2x−3)−(1)(2x−3) =2x3−3x2−2x+3