Simplify $x (2 x^{2} - 7 x + 3)$ and find the values of it for $x = 0$

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Solution

$x (2 x^{2} - 7 x + 3)$

$= x (2 x^{2} - 6 x - x + 3)$

$= x [2 x (x - 3) - 1 (x - 3)]$

$= x (2 x - 1) (x - 3)$

At $x = 0$ ,the above expression equals $0$

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Similar questions

3 x (4 x - 5) + 3

x = 3

3 x (4 - 5 x) + 6

x = 3

3 x (4 x - 5) + 3

x = 3

x = \frac{1}{2}

a (a^{2} + a + 1) + 5

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(a) Simplify 3x (4x −5) + 3 and find its values for (i) x = 3, (ii) .

(b) a (a² + a + 1) + 5 and find its values for (i) a = 0, (ii) a = 1, (iii) a = − 1.

3 x (4 x - 5) + 3

x = \frac{1}{2}

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