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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
Simplify: x2...
Question
Simplify:
x
2
+
x
−
(
p
2
−
5
p
+
6
)
Open in App
Solution
Now,
x
2
+
x
−
(
p
2
−
5
p
+
6
)
=
x
2
+
x
−
(
p
−
3
)
(
p
−
2
)
=
x
2
+
{
(
p
−
2
)
−
(
p
−
3
)
}
x
−
(
p
−
3
)
(
p
−
2
)
=
(
x
+
p
−
2
)
(
x
−
p
+
3
)
.
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Similar questions
Q.
Factorise :
p
2
+
5
p
+
6
Q.
For which values of
p
is
p
2
−
5
p
+
6
negative?
Q.
Simplify:
(
5
p
2
−
25
p
+
20
)
÷
(
p
−
4
)
.
Q.
Let
α
+
1
and
1
α
+
1
be the roots of
x
2
−
2
(
p
+
1
)
x
+
5
p
−
p
2
=
0
for non-zero
α
.
If
f
:
R
→
[
0
,
∞
)
defined by
f
(
x
)
=
x
2
−
2
(
p
+
1
)
x
+
5
p
−
p
2
is surjective function, then
p
can be
Q.
The perimeter of a triangle is
7
p
2
−
2
p
+
6
units and the length of two of its adjacent sides are
2
p
2
−
2
p
+
3
units and
3
p
2
−
5
p
+
2
units. Find the length of the third side of the triangle?
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