CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify (x+2y+3z)(x2+4y2+9z22xy6yz3zx)

Open in App
Solution

We know that, (x+y+z)(x2+y2+z2xyyzzx)=x3+y3+z33xyz
(x+2y+3z)(x2+4y2+9z22xy6yz3zx)
=(x+2y+3z)[x2+(2y)2+(3z)2(x)(2y)(2y)(3z)(3z)(x)]
=(x3)+(2y)3+(3z)33(x)(2y)(3z)
=x3+8y3+27z318xyz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon