Question

Simplify:

$x+7-\frac{8x}{3}=\frac{17x}{6}-\frac{5x}{8}$

Answer 1

We have,

$x+7-\frac{8x}{3}=\frac{17x}{6}-\frac{5x}{8}$

$x+7-\frac{8x}{3}=\frac{68x-15x}{24}$

$x+7-\frac{8x}{3}=\frac{68x-15x}{24}$

$x+7=\frac{8x}{3}+\frac{53x}{24}$

$x+7=\frac{64x+53x}{24}$

$x+7=\frac{117x}{24}$

$\frac{117x}{24}-x=7$

$\frac{117x-24x}{24}=7$

$\frac{93x}{24}=7$

$93x=7\times 24$

$x=\frac{168}{93}$

Hence, this is the answer.