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Question

Simplify:
(xa+b)ab.(xb+c)bc.(xc+a)ca

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Solution

As given (xa+b)ab.(xb+c)bc.(xc+a)ca
(x(a+b)(ab)).(x(b+c)(bc)).(x(c+a)(ca))
(xa2+ababb2).(xb2+bcbcc2).(xc2+acaca2)
(xa2b2).(xb2c2).(xc2a2)
(xa2b2+b2c2+c2a2)
x0
a0=1
x0=1

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