Simplify :
$x (x^{2} + 2 x + 2) + 5$ find value when x = 0, x = -1

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Solution

$f (x) = x (x^{2} + 2 x + 2) + 5$
$f (0) = 0 (0 + 0 + 2) + 5 = 0 + 5 = 5$
$f (- 1) = - 1 ({(- 1)}^{2} + 2 \times - 1 + 2) + 5 = - 1 (1 - 2 + 2) + 5 = - 1 + 5 = 4$

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