Simplify : $x (x^{2} + x + 2) + 5$ find its value when $x = 0, x = - 1$

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Solution

$f (x) = x (x^{2} + x + 2) + 5$

$f (0) = 0 (0^{2} + 0 + 2) + 5 = 0 + 5 = 5$

$f (- 1) = (- 1) ({(- 1)}^{2} + (- 1) + 2) + 5 = - 1 (1 - 1 + 2) + 5 = - 2 + 5 = 3$

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Similar questions

(a) Simplify 3x (4x −5) + 3 and find its values for (i) x = 3, (ii) .

(b) a (a² + a + 1) + 5 and find its values for (i) a = 0, (ii) a = 1, (iii) a = − 1.

x (x^{2} + x + 1)

x = 2

3 x (4 x - 5) + 3

x = 3

x = \frac{1}{2}

a (a^{2} + a + 1) + 5

a = 0

a = 1

a = - 1

3 x (4 x - 5) + 3

x = \frac{1}{2}

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