Simplify: (xy+yz)2 - (xy−yz)2
4xy2z
For the expression (xy+yz)2
We use the identity (a+b)2 = a2 + b2+2ab
Hence we get x2y2 + y2z2 + 2xzy2 ......................1;
For the expression (xy−yz)2 we use the edentity (a−b)2=a2 + b2−2ab
Hence we get x2y2 + y2z2 - 2xzy2...........2;
Subtracting 2 from 1, we get:
(x2y2 + y2z2 + 2xyz2) - (x2y2 + y2z2 −2xzy2) = 4xy2z