Simplify: $y {(x - 2 y)}^{2} - 13 + 4 (x - 1)$

Open in App

Solution

Given: $y (x - 2 y)^{2} - 13 + 4 (x - 1)$

$= y (x^{2} - 4 x y + 4 y^{2}) - 13 + 4 x - 4$

$= x^{2} y - 4 x y^{2} + 4 y^{3} - 13 + 4 x - 4$

$= 4 y^{3} - 4 x y^{2} + x^{2} y + 4 x - 17$ .

Suggest Corrections

Similar questions

{(4 x + y)}^{2} + (4 x + y) (x + 2 y) - 20 {(x + 2 y)}^{2}

(4 x + 2 y)^{2}

{(x - 2 y)}^{2} - 4 x + 8 y

(4 x - 2 y) (5 x + 4 y) - (3 x^{2} + 2 y^{2})

9 {(x - 2 y)}^{2} - 4 (x - 2 y) - 13

Join BYJU'S Learning Program

Related Videos

Addition and Subtraction of Algebraic Expression

MATHEMATICS

Watch in App

Explore more

Join BYJU'S Learning Program