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B
1−xy
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C
1+xy
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D
1+xyz
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Solution
The correct option is B1−xy Given, the expression is z−19+19xy−xyz(z−19). Now, the numerator can be factorized as, z−19+19xy−xyz =1(z−19)−xy(−19+z) =1(z−19)−xy(z−19) =(1−xy)(z−19) Therefore, z−19+19xy−xyz(z−19)=(1−xy)(z−19)(z−19)=1−xy