Question

$Simplify:(z-19+19xy-xyz)÷(z-19)$

• A. $1-xyz$
• B. $1-xy$
• C. $1+xy$
• D. $1+xyz$

Answer 1

The correct option is B $1-xy$

Given: $\frac{z-19+19xy-xyz}{(z-19)}.$
Now, the numerator can be factorized as,
$z-19+19xy-xyz$
$=1(z-19)-xy(-19+z)$
$=1(z-19)-xy(z-19)$
$=(1-xy)(z-19)$
Therefore,
$\frac{z-19+19xy-xyz}{(z-19)}=\frac{(1-xy)(z-19)}{(z-19)}=1-xy$