Simplifyi:(7+3√5\3+√5)+(7-3√5\3-√5
Q. (7 + 3√5) / (3 + √5) + (7 - 3√5) / (3 - √5)
Taking LCM (3 + √5) (3 - √5) and adding we get,
{(7 + 3√5) (3 - √5) + (7 - 3√5) (3 + √5)} / (3 + √5) (3 - √5)
Solving this we get,
12 / 3^2– (√5)^2[(3 + √5) (3 - √5) = 3^2 – (√5)^2using identity (a +b) (a – b) = a^2– b^2]
=12 / 9 – 5
=12 / 4
= 3
(Answer)